Matematică, întrebare adresată de neculaluana5, 9 ani în urmă

Ce se poate din ce e incercuit dau coronița cand imi apare

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Răspunsuri la întrebare

Răspuns de carmentofan
0

Răspuns:

Explicație pas cu pas:

10.

2x - 1 ≥ 7

2x ≥ 8

x ≥ 4

___________

2x + 3 ≥ -9

2x ≥ -12

x ≥ -6

___________

3x - 1 ≥ 8

3x ≥ 9

x ≥ 3

____________

4x + 1 < 9

4x < 8

x < 2

____________

5x - 9 < -24

5x < -15

x < -3

____________

3 + 4x ≥ 7

4x ≥ 4

x ≥ 1

____________

6 + 2x ≥ 0

2x ≥ -6

x ≥ -3

______________

-5 + 3x < -8

3x < -3

x < -1

_______________

2x - 7 ≥ -19

2x ≥ -12

x ≥ -6

________________

-11 + 12x < -23

12x < -12

x < -1

______________

1 - 7x ≥ -20

7x ≤ 21

x ≤ 3

____________

3 - 4x < 7

4x > -4

x > -1

____________________________

11.

2x - 2 < -6

2x < - 4

x < -2

___________

3x + 3 < -18

3x < - 21

x < -7

____________

4x + 8 ≥ -8

4x ≥ -16

x ≥ -4

____________

2x + 16 ≤ -10

2x ≤ -26

x ≤ -13

__________

5x - 5 < 0

5x < 5

x < 1

__________

2x + 10 + 3 < -9

2x <-22

x < -11

__________

3 + 2x + 4 < 5

2x < -2

x < -1

____________

1 + 4x - 4 < -7

4x < -4

x < -1

____________

10 - 15x < -5

15x > 15

x > 1

______________________

12.

x > -80/3

_____________

x < 1/5

_____________

x ≤ -3/2

_____________

x ≥ -10/7

___________

3x > -13

x > -13/3

___________

5x ≤ 2

x ≤ 2/5

___________

5x ≤ 14

x ≤ 14/5

__________

6x - 3 ≤ x -14

5x ≤ -11

x ≤ -11/5

Răspuns de targoviste44
1

\it 10)\ x\in\mathbb{Z}\\ \\ a)\ 2x-1\geq7 \Rightarrow 2x\geq8 \Rightarrow x\geq4 \Rightarrow S=\{4,\ 5,\ 6,\ ...\}\\ \\ b)\ 2x+3\geq-9 \Rightarrow 2x\geq-12 \Rightarrow x\geq-6 \Rightarrow S=\{-6,\ -5,\ -4,\ -3,\ ...\}\\ \\ c)\ 3x-1\geq8 \Rightarrow 3x\geq9 \Rightarrow x\geq3 \Rightarrow S=\{3,\ 4,\ 5,\ ...\}\\ \\ d)\ 4x+1&lt;9 \Rightarrow 4x&lt;8 \Rightarrow x&lt;2 \Rightarrow S=\{...,\ -2,\ -1,\ 0,\ 1\}

\it k)\ 1-7x\geq-20 \Rightarrow -7x\geq-21|_{\cdot(-1)} \Rightarrow 7x\leq21 \Rightarrow x\leq3 \Rightarrow \\ \\ \Rightarrow S=\{...,\ -2,\ -1,\ 0,\ 1,\ 2,\ 3\}

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