Question

Ce volum de aer cu 20% oxigen se consuma la arderea a 222g amestec echimolecular de etan(C2H6) si propan(C3H8)?

Answer 1

Amestec echimolecular==>x=y
MC2H6=30g/mol
MC3H8=44g/mol

30x+44y=222==>74x=222==>x=3 moli si y=3 moli

1mol..........7/2mol
CH3-CH3 + 7/2O2 -->
3mol...........x=10.5mol
2CO2 + 3H2O + Q

n=V/Vmolar==>V=n*Vmolar=10.5*22.4=235.2 L O2

Vaer=5*VO2=5*235.2=1176 L
1mol.......5mol
C3H8 + 5O2 --> 3CO2
3mol......x=15mol
+ 4H2O + Q

n=V/Vmolar==> V=n*Vmolar=15*22.4=336L O2

Vaer=5*VO2=5*VO2=1680L

Vaer necesar arderi (C2H6+C3H8)= Vaer C2H6 + Vaer C3H8= 1176+1680=2856L aer