Question

Ce volum de clor ,la 2 atmosfere si 227 de grade celsius se consuma la ardere in hidrogen pentru a forma 6 moli de HCL( Dau coroana)

Answer 1

Cl2 + H2 => 2HCl

1 mol Cl2 .... 2 mol HCl
x mol Cl2 ......6 mol HCl
x= 3 mol Cl2

pV=nRT => V = nRT/p
p= 2 atm
n= 3 mol Cl2
T= t + 273 K = 227+273K =500 K
R=0.082 L x atm / mol x K
V = 3 x 0.082 x 500 / 2 = 61.5 L