Question

Ce volum de CO2 (conditii normale) se obtine la arderea unui kilogram de carbune care contine 80% carbon?

Answer 1

C + O2 = CO2 1 kg=1000 g; => m pur cărbune = (1000•80)/100= 800 g M C= 12; M CO2= 12 +16•2=44 => masa de CO2= 800•44/12= 2933,33 grame