Question

Ce volum ocula in conditi normale
a) 5 moli NH3
b) 51 g NH3
c) 12,046×10 la puterea 23 molecule NH3

Answer 1

Răspuns:

n=m : M    ; n=nr.moli  ;     m=masa subst.   ;   M=masa molara

Explicație:

a.

VNH3=5moli. 22,4L/moli=112L

b.

n=51g : 17g/moli=3moli NH3

VNH3=3moli.22,4L /moli=67,2 L

C.

n= 12,046 .10²³ : 6,023.10²³=2moli NH3

VNH3=2moli.22,4L/moli=44,8L

MNH3=14 +3= 17----->17g/moli