Question

Ce volum ocupa la 27 grade Celsius si 4 atm 128 kg oxigen? Va rog!!

Answer 1

1) Transformi gradele Celsius in grade Kelvin

2) Aflii cati moli de O2 inseamna 128 kg oxigen

3) Aplici formula gazului ideal

1) 27 Celsius -> 300 Kelvin (273 + 27)

2) O2 = 16 x 2 =32 g

128 kg = 128000 g

128000/32 = 4000 moli de O2

3) V = nRT/P

unde R reprezinta constanta gazului ideal care este 0.0821

V = 4000 x 0.0821 x 300 / 4 = 24300 L