Question

Ce volum va avea solutia de HCl de c= 36.5% si densitate 1.18g/mol, necesar prepararii a 100cm^3 solutie de HCL concentratie 0.5M?

Answer 1

Vs = 100 cm3 = 0,1 L, Cm = 0,5 mol/L

stim ca Cm = niu/Vs

=> niu = CmxVs = 0,5x0,1 = 0,05 moli HCl

miu.HCl = 36,5 g/mol

md.HCl = miuxniu

= 0,05x36,5 = 1,825 g HCl

stim ca c% = mdx100/ms

=> ms = mdx100/c%

= 1,825x100/36,5 = 5 g sol. HCl

ro = ms/Vs

=> Vs = ms/ro

= 5/1,18 = 4,24 cm3 sol. HCl