Question

Ce volum va ocupa solutia de acid clorhidric de concentratie 18,25%si densiatate 1,194 g/cm³ ce va reactiona cu 325 g zinc cu 20%impuritati

Answer 1

80/100*325=260g Zn pur

n=m/M=260/65=4 moli Zn pur

Zn + 2HCl => ZnCl2 + H2

1 mol Zn......................2*36,5g HCl
4 moli Zn........................x=292g HCl

C=md/ms*100=>ms=md*100/C=29200/18,25=1600g HCl

ro=ms/V => V=ms/ro=1600/1,194=1340,033 cm3 = 1,34L sol. HCl