Question

cel mai mic nr natural al solutiei a inecuatiei [3•(x+19)]:3>sau=31

Answer 1

3(x+19):3≥31

3x+57≥93

3x≥36

x≥12

x∈{12}

Answer 2

$\big[3\cdot(\text{x}+19)\big]:3\geq31 \\ \\ \text{x}+19 \geq 31 \\ \\ \text{x}\geq 31-19 \\ \\ \text{x} \geq 12,\quad dar , \text{x} \in \mathbb_{N} \Rightarrow \text{x}\in \Big\{12,13,14,15,16,...\Big\} \\ \\ \Rightarrow Cel mai mic nr. natural al solutiei a inecuatiei, este 12.$