Question

Cel mai mic numar natural care impartit la 12 da restul 8 iar impartit la 10 da restul 6 are suma cifrelor:

Answer 1

n=12·c1+8=10·c2+6
n+4=12·c1+12=10·c2+10
n+4=12(c1+1)=10(c2+1)
n+4=[12,10]
n+4=60
n=60-4
n=56
suma cifrelor=5+6=11
R: suma cifrelor=11