Question

Cele 2 exercitii incercuite. Multumesc!

Answer 1

n1moli  C2H4
n2moli  C2H2 + H2 = C2H4
n3 moli H2
n1/1 = n2/2 = n3/5 = n/8     n = 179,2/22,4 = 8kmoli   
n1 = 1kmol; n2=2kmoli;  n3 = 5kmoli
amestec gazos final : C2H4 (n1+n2 = 3kmoli);   H2 (n3 -n2 = 3kmoli)
%C2H4 = 3·100/6 = 50%      %H2 = 50%
44.  R-C≡CH +Na ⇒  R-C≡Na + 1/2H2
n alchena = 2nH2
3,4/M = 2·0,56/22,4     M = 68g/mol      CxH(2x-2)     14x - 2 = 68    x = 5
HC≡C-CH(CH3)-CH3