Question

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Prin izomerizarea a 116g n-butan, rezulta 1,8 moli izo-butan (metil-propan). Calculeaza randamentul reactiei

Answer 1

masa molara n-butan = C4H10 = 2x14 + 10 = 48 + 10 = 58 g/mol

116g....xmoli

58g....1 mol => x = 2 moli

2 moli n-butan.........................1,8moli i-butan

deci

2 moli i-butan.............100%

1,8moli.................x%

x= 1,8x100/2 = 90%