Question

chimie, ambele va rog​

Answer 1

Răspuns:

1.

MNa=23g/mol

MCl2=2×35,5=71g/mol

MNaCl=23+35,5=58,5g/mol

2×23g    71g       2×58,5g  

2Na   +    Cl2  →  2NaCl

600g      xg           yg

x=600×71/2×23=calculeaza

y=600×2×58,5/2×23= calculeaza

2.

ms=540g

C=60%

md=?

md=C×ms/100=540×60/100=324gNaOH

MNaOH=23+16+1=40g/mol

MNa2SO4=2×23+32+4×16=142g

2×40g                  142g

2NaOH+H2SO4→Na2SO4+2H2O

342g                    xg

x=342×142/2×40= calculeaza

Explicație:

Answer 2

Răspuns:

Explicație:

1.

600g Na

react. cu Cl2

masa de clor

masa de sare

600g         xg       yg

2Na     + Cl2     =2 NaCl

2.23g    2.35,5g     2. 58,5 g

x= 600. 71 : 46 =926,08 g Cl

y=600.117 : 46=1526,08 g NaCl

2.

540g  sol. NaOH

c=60%

react. cu H2SO4

masa de sare

-se afla  md  sol. de NaOH

md= c.ms :100

md= 60 . 540 : 100=324 g NaOH

324g                           xg

2NaOH + H2SO4= Na2SO4 +2 H2O

2.40g                           142g

x= 324 . 142 : 80=575 ,1 g Na2SO4

n= 575,1g : 142g/moli=4,05 moli sare

M NaCl= 23 + 35,5= 58,5 ------> 58,5g/moli

MNaOH= 23 + 16 +1=40-------> 40g/moli

MNa@SO4= 2.23 + 32 + 4.16=142------> 142g/moli

verifica calculele  !!!!!!