Question

Chimie: Cine stie ex IV? Please.

Answer 1

1) CH2=CH-CH2-CH3
Izomeri
CH3-CH=CH-CH3 (izomeri cis, trans)
CH2=C(CH3)-CH3
=> 1-butena este alchena
2) A + HBr => CH3-CH(Br)-CH2-CH3            2-bromobutan
B (NaOH) => CH3-CH=CH-CH3 + HBr          2-butena
C + H2O => CH3-CH(OH)-CH2-CH3             2-butanol
3) ppuritatea = m pura/m impura * 100
m pura = 300*56/100 = 168 g A
M A = 4*12+8*1 = 56
M D = 4*12+10*1+16 = 74
56 g A............74 g D
168 g A.............a
a = 222 g D