Question

Chimie cls a 8-a!!!​

Answer 1

Răspuns:

Explicație:

-se afla nr. de moli CH4

n=67,2L : 22,4L/moli=3 moli CH4

MCH4=12 +4=16----->16g/moli

mCH4=3moli . 16=48 g CH4

xg     yg       48g

C + 2H2  = CH4

12g   2.2g    16g

x=12.48 : 16=36 g C  

n=36g : 12g/moli=3 moli C

-se afla mp carbune

mp=p.mi :100

mp=72 .200 : 100=144g C pur

C este in exces-----> 144g - 36=108g C in exces

y=48 .4 : 16=12g hidrogen

n=12g : 2g/moli=6 moli H2

VH2=6moli .22,4 L/moli=134,4 L