Question

Chimie:exercitiile 7,8;​

Answer 1

7/.

PV = nRT

n = V/Vm, VM = volumul molar

= 350/22,4 = 15,625 moli O2

=> P = nRT/V = 15,625x0,082x(273+20)/10

= 37,5 atm

8/.

a moli    b moli  360 g

2H2   +   O2 => 2H2O

2           1             2x18

=> a = 2x360/2x18 = 20 moli O2

=> b = 1x360/2x18 = 10 moli H2

amandoua calculate in conditii normale .... dar ce volum vor ocupa in conditiile date in probelma...??

pt. H2:

PV = nRT => V = nRT/P

= 10x0,082x(273+127)/2

= 164 L H2

pt O2:

PV = nRT => V = nRT/P

= 20x0,082x(273+127)/2

= 328 L O2