Question

cine ajută fac promovare dau coroana dor cîteva sale faceti​

Answer 1

Răspuns:

Explicație pas cu pas:

1) Se aplica log  in baza a:

b*log(a;a) = log(a;c),  b = log(a;c), raspuns C.

2) (-2)^(15/9) = (-2)^(5/3) , raspuns A.

3) 2/6 = 1/3 < 1

Daca x < y,  (1/3)^x > (1/3)^y,  raspuns A.

4) a^(log(a;b) = b

36 = 6^2

6^(2*log(6;5) = 6^(log(6;5^2) = 5^2 = 25

10/(10^(lg2) = 10/5 = 2         (lg = log in baza 10)

36 = 9*4

3(log(9;9) +log(9;4)) = 3^(1 +log(9;4)) = 3*3^(log(9;4))

log(9;4) = log(3;4)/log(3;9) = log(3;4)/log(3;3^2) =

 log(3;4)/2 = log(3;4^(1/2))

3^ log(3;4^(1/2)) = 2

3*3^(log(9;4)) = 3*2 = 6

In final: 25 +2 -6 = 21