Question

Cine imi poate rezolva si mie exrcitille incercuite va rog? dau 40 de puncte as ramane recunoscator daca se poate pana in ora 13:00-14:00 am nevoie de ele raman recunoscator.

Answer 1

5. c) 4*$\frac{2}{3}$-0,(3)=$\frac{8}{3}$-$\frac{3}{9}$=$\frac{24}{9}$-$\frac{3}{9}$=$\frac{24-3}{9}$=$\frac{21}{9} = \frac{7}{3}$
d) $\frac{26-2}{9}$-$\frac{4}{3}$=$\frac{24}{9} - \frac{4}{3} = \frac{24}{9} - \frac{12}{9} = \frac{12}{9} = \frac{4}{3}$
7. b) 5$\sqrt{3}$ - 2$\sqrt{3}$ =3$\sqrt{3}$ 
c)4 $\sqrt{5}$ + 5$\sqrt{5}$ = 9$\sqrt{5}$
e) 4$\sqrt{7}$ - 8$\sqrt{7}$ = -4$\sqrt{7}$
f) 3$\sqrt{6}$-9$\sqrt{6}$ = -6$\sqrt{6}$
h) -$\sqrt{3}$-14$\sqrt{3}$ = -15$\sqrt{3}$
i) -10$\sqrt{5}$-$\sqrt{5}$ = -11$\sqrt{5}$

8. b) 4$\sqrt{3}$-8$\sqrt{3}$+2$\sqrt{3}$ = -4$\sqrt{3}$+2$\sqrt{3}$ = -2$\sqrt{3}$
d) -7$\sqrt{6}$+2$\sqrt{6}$+5$\sqrt{6}$ = -5$\sqrt{6}$+5$\sqrt{6}$=0
f) -2$\sqrt{5}$+6$\sqrt{5}$-12$\sqrt{5}$ = 4$\sqrt{5}$-12$\sqrt{5}$ = -8$\sqrt{5}$
10. b) $\sqrt{27} + 2 \sqrt{12} = 3 \sqrt{3} + 2*2 \sqrt{3} = 7 \sqrt{3}$
c) $\sqrt{20} - 4\sqrt{45} = 2 \sqrt{5} - 4*3 \sqrt{5} = -10 \sqrt{5}$
e) $\sqrt{28} - 12 \sqrt{63} = 2 \sqrt{7} - 12*3\sqrt{7} =-34\sqrt{7}$
f) $- \sqrt{75} +3 \sqrt{48} = -5 \sqrt{3} + 3*4\sqrt{3} =7\sqrt{3}$
h) [tex] \sqrt{125} - 6 \sqrt{80} = 5 \sqrt{5} - 6*4\sqrt{5} = -19\sqrt{5} [/tex]
i) $- \sqrt{96} -4 \sqrt{54} = -4 \sqrt{6} -4*3 \sqrt{6} = -16 \sqrt{6}$