Question

cine imi rezolva 1 ex?​

Answer 1

Răspuns:

Explicație pas cu pas:

$\bf a)~~\bigg(5^{17} \cdot5^{18}+7^{23}:7^{15}\bigg):\bigg(7 \cdot7^{2}\cdot7^{5}+5^{50}:5^{15}\bigg)=$

$\bf \bigg(5^{17+18} +7^{23-15}\bigg):\bigg(7^{1+2+5}+5^{50-15}\bigg)=$

$\bf \bigg(5^{35} +7^{8}\bigg):\bigg(7^{8}+5^{35}\bigg)=$

$\bf \bigg(7^{8}+5^{35} \bigg):\bigg(7^{8}+5^{35}\bigg)=$

$\red{\Large\boxed{\bf 1}}$

$\it~~~$

$\bf b)~~\Bigg[\bigg(2^{10} \bigg)^{8}+6^{5}\cdot3^{7}+2^{3^{2}}\Bigg]:\Bigg[\bigg(2^{5} \bigg)^{16}+6^{12}:2^{7}+2^{9}\Bigg]=$

$\bf\bigg(2^{10\cdot8}+2^{5}\cdot3^{5}\cdot3^{7}+2^{9}\bigg):\bigg(2^{5\cdot 16}+2^{12}\cdot3^{12}:2^{7}+2^{9}\bigg)=$

$\bf\bigg(2^{80}+2^{5}\cdot3^{5+7}+2^{9}\bigg):\bigg(2^{80}+2^{12-7}\cdot3^{12}+2^{9}\bigg)=$

$\bf\bigg(2^{80}+2^{5}\cdot3^{12}+2^{9}\bigg):\bigg(2^{80}+2^{5}\cdot3^{12}+2^{9}\bigg)=$

$\pink{\Large\boxed{\bf 1}}$

$\it~~~$

$\red{\Large \bf \star ~\underline{Formule~pentru~puteri}:}$

$\Large \bf a^{0} = 1;$

$\Large \bf (a^{n})^{m} = a^{n \cdot m};$

$\Large \bf a^{n}\cdot a^{m} =a^{n+m};$

$\Large \bf a^{n}: a^{m} =a^{n-m}$

$\it~~$

P.S.: Dacă ești pe telefon te rog să glisezi spre stânga pentru a vedea întreaga rezolvare.

#copaceibrainly