Question

Cine îmi rezolvă acest exercițiu pas cu pas corect,cu rezolvare de clasa aVa primește 95 puncte​

Answer 1

Răspuns:

a)x^2:4=9

x^2=9×4

x^2=36

x=radical din 36

x=6

b)25^2-x=24^2

625-x=576

-x=576-625

-x=-49

x=49

c) x:10^3=10^0

x:100=1

x=1×100

x÷100

d)441:x=21^2

441:x=441

x=441:441

x=1

e) x-2^5=5^3

x-32=125

x=125+32

x=157

f)324:x=3^2

324:x=9

x=324:9

x=36

Explicație pas cu pas:

sper sa te ajute

Answer 2

Salutare!

(a)

$\bf x^{2} :2^{2} =3^{2}$

$\bf x :2 =3\:\:\Big|\cdot 2 \:\: \text{(\it inmultim toata relatia cu 2)}$

$\bf x :2 \cdot 2 =3 \cdot 2$

$\boxed{\bf x =6}$

(b)

$\bf 25^{2} -x =24^{2}$

$\bf 625 -x =576$

$\bf 625 =576+x$

$\bf x=625 -576$

$\boxed{\bf x=49}$

(c)

$\bf x :10^{3} =10^{0}\:\:\Big|\cdot 10^{3}$

$\bf x =10^{0}\cdot 10^{3}$

$\bf x =10^{0+3}$

$\boxed{\bf x =10^{3}}$

(d)

$\bf 441 :x = 21^{2}$

$\bf 441 :x = 441\:\:\Big|\cdot x$

$\bf 441= 441\cdot x$

$\bf x = 441: 441$

$\boxed{\bf x = 1}$

(e)

$\bf x-2^{5} = 5^{3}$

$\bf x-32 = 125$

$\bf x = 125+32$

$\boxed{\bf x = 157}$

(f)

$\bf 324 :x = (3^{2}\cdot 2)^{2}$

$\bf 324 :x = (9\cdot 2)^{2}$

$\bf 324 :x = 18^{2}$

$\bf 324 :x = 324$

$\bf x=324:324$

$\boxed{\bf x=1}$

PS: la punctul f) nu se vede foarte bine ce este dupa egal si am scris eu cum ar fi completarea acestui subpunct

==pav38==