Question

cine imi rezolva si mie exercitiul 1?

Answer 1

a) (2x-1)² = (2x)²-2*2x*1+1²=4x²-4x+1
b) (x+√3)² = x²+2x√3+√3² = x²+2√3x+3
c) (a²-a+2)²=a^4+(-a²)+4-2a³+4a²-4a
= a^4+a²+4-2a³+4a^4-4a=a^4+5a²+4-2a³-4a=a^4-2a³+5a²-4a+4
d) ( 2x-7)(2x+7)=(2x)²-7²=4x²-49
e) (a-2b)²=a²-2a+2b+(2b)² = a²-4ab+4b²
g) (3x-2)²=(3x)²-2*3x*2+2²=9x²-12x+4
i) (√2x+3)²=√2x²+2√2x*3+3²=2x+6√2x+9
h) (x²+x-3)²=x^4+x²+9-2x³-6x²-6x=x^4-5x²+9+2x³-6x=x^4+2x³-5x²-6x+9
f) ( x+2√2)(x-2√2)=x-2√2x+2√2-2√2*2√2=x-2√2x+2√2-8


Succes!!

„CLAUAND„