Question

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Answer 1

$4\frac{4-5x}{3}+5\frac{5-4x}{3}=3$
$\frac{12+4-5x}{3}+\frac{15+5-4x}{3}=3$
$\frac{16-5x}{3}+\frac{20-4x}{3}=3$
$\frac{16-5x+20-4x}{3}=3$
$\frac{36-9x}{3}=3$
$36-9x=9$
$9x=27$
$x=3$

Answer 2

$\it 4\dfrac{4-5x}{3} +5\dfrac{5-4x}{3} =3 \Leftrightarrow (4+5) +\left(\dfrac{4-5x+5-4x}{3}\right) =3 \Leftrightarrow \\\;\\ \\\;\\ \Leftrightarrow 9+\dfrac{9-9x}{3} =3 \Leftrightarrow 9+\dfrac{3(3-3x)}{3} =3 \Leftrightarrow 9+3-3x=3 \Leftrightarrow \\\;\\ \\\;\\ \Leftrightarrow 12-3x=3|_{:3} \Leftrightarrow 4-x=1 \Leftrightarrow x = 3.$