Matematică, întrebare adresată de rosud7060, 8 ani în urmă

Cine ma ajuta are 74 de puncte​

Anexe:

Răspunsuri la întrebare

Răspuns de stefanitatudor2009
2

Salut! Te voi ajuta eu!

\frac{4}{6} > \frac{4}{5}

\frac{8}{8} = \frac{2}{2}

\frac{4}{5} > \frac{3}{5}

\frac{7}{7} > \frac{2}{3}

\frac{3}{8} < \frac{4}{8}

\frac{5}{9} < \frac{5}{8}

\frac{2}{9} < \frac{2}{8} < \frac{2}{3}

\frac{6}{7} > \frac{5}{7} > \frac{2}{7}

\frac{10}{8} < \frac{10}{9} < \frac{10}{4}

Sper că te-am ajutat!


rosud7060: va mulțumesc foarte mult mati ajutat la timp
Răspuns de pav38
34

Răspuns:

Explicație pas cu pas:

\large \bf  \dfrac{4}{6} ~~\boxed{\bf &gt;}~~ \dfrac{4}{5}

\large \bf  \dfrac{8}{8} ~~ \boxed{\bf =} ~~ \dfrac{2}{2}

\large \bf  \dfrac{4}{5}  ~~\boxed{\bf &gt;}  ~~\dfrac{2}{5}

\large \bf  \dfrac{7}{7}  ~~\boxed{\bf &gt;} ~~ \dfrac{1}{3}

\large \bf  \dfrac{3}{8}  ~~\boxed{\bf &lt;} ~~ \dfrac{5}{8}

\large \bf  \dfrac{5}{10}  ~~\boxed{\bf &lt;}  ~~\dfrac{5}{8}

\large \bf  \dfrac{9}{8} ~~ \boxed{\bf &gt;}  ~~\dfrac{3+2}{9}~~ \boxed{\bf &gt;} ~~\dfrac{4}{9}

\large \bf  \dfrac{2}{9} ~~ \boxed{\bf &lt;}  ~~\dfrac{2}{7}~~ \boxed{\bf &lt;} ~~\dfrac{2}{3}

\large \bf  \dfrac{6}{7}  ~~\boxed{\bf &gt;}  ~~\dfrac{4}{7}~~ \boxed{\bf &gt;}~~ \dfrac{2}{7}

\large \bf  \dfrac{10}{8}  ~~\boxed{\bf &lt;}  ~~\dfrac{10}{7-2}~~ \boxed{\bf &lt;} ~~\dfrac{10}{4}

==pav38==

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