Question

Cine ma ajuta cu problema 4 punctul B dau funda va multumesc enorm am nevoie in aceasta seara va rog
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Answer 1

Răspuns:

AM mediana =>Aamb=Aamc=Aabc/2

Aamb =(am ×be) /2

be perpendicular pe am

Aamc=(am×cf) /2

cf perpendicular pe am

Aamb=Aamc =>(am×be)/2 = (am×cf)/2=> am×be=am ×cf =>be = cf => d(B,AM) =d(C,AM)