Question

Cine ma ajuta cum sa rezolv exercitii cu rationalizarea numitorilor?

Answer 1

$\frac{6}{ \sqrt{3} } = \frac{6 \sqrt{3} }{3} =2 \sqrt{3}$

practic,am inmultit cu √3 pentru ca √3x√3=3

Answer 2

[tex] 1)^{\sqrt{b})}\frac{1}{a\sqrt{b}} = \frac{\sqrt{b}}{a \cdot b} \\ ^{\sqrt{2})}\frac{1}{2\sqrt{2}} = \frac{\sqrt{2}}{2 \cdot 2}=\frac{\sqrt{2}}{4}\\ 2)^{a-\sqrt{b})}\frac{1}{a+\sqrt{b}} = \frac{a-\sqrt{b}}{a^2 -b}\\ ^{a+\sqrt{b})}\frac{1}{a-\sqrt{b}} = \frac{a+\sqrt{b}}{a^2 -b}\\ ^{3-\sqrt{8})}\frac{1}{3+\sqrt{8}} = \frac{3-\sqrt{8}}{3^2 -8}=3-\sqrt{8} [/tex]