Question

Cine ma ajuta sa rezolve ce e incercuit primeste coroana va rog este rapid

Answer 1

Răspuns:

Explicație pas cu pas:

a) 16+(-6+9):(-2-1)+(-7)·(-5+9)  = 16+3:(-3) + (-7)·4 = 16-1-28 = -13

b) -8-(-6-8):(4-6)+I-6+3I:(-1) = -8-(-14):(-2) + I-3I:(-1) = -8-7+3:(-1) =

= -15-3 = -18

c) 21-(+4-10)·(-5+15):(-2-1)-(8-9)·(+5) = 21-(-6)·10:(-3) -(-1)·5 =

= 21-(-60):(-3)+5 = 21-20+5 = 6

d) -13+(-5-9+8):(-2+5)-(-16+I-7+2I:5) = -13+(-6):3-(-16+5:5) =

= -13-2-(-15) = -15+15 = 0

e) 4-[-44-(-25)·(-4)]:24-(-9-11): I-6+1I = 4-[-44-100]:24-(-20): I-5I =

= 4-(-144):24-(-20):5 = 4+6+4 = 14

f) -3+[36-(-12)·3+(-6+2)·(-13-8)]·I-2+I-8+3II =

= -3+[36-(-36)+(-4)·(-21)]·I-2+I-5II = -3+[36+36+84]·I-2+5I =

= -3+156·3 = -3+468 = 465

a) ab+ac = -12 ; b+c = -3 ; a = ?

ab+ac = a·(b+c) => a = (ab+ac):(b+c) = -12:(-3) = 4 => a=4

b) ab-ac = 28 ; a = -4 ; b-c = ?

ab-ac = a·(b-c) => b-c = (ab-ac):a = 28:(-4) = -7 => b-c = -7

c) ab+ac-ad = -16 ; a = d = -8 ; b+c = ?

ab+ac-ad = a·(b+c-d) = > b+c-d = (ab+ac-ad):a = -16:(-8) = 2

=> b+c = 2+d = 2-8 = -6 => b+c = -6

d) 2ac+2bc = -32 ; a+b = 4 ; c = ?

2ac+2bc = 2c·(a+b) =>

c = (2ac+2bc):[2·(a+b)] = -32 :(2·4) = -32:8 = -4 =>

c = -4

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