Question

Cine ma ajuta si pe mine . Imi trebuie urgent aceasta teme .

Answer 1

nr. de moli  = n

n=m:M              [  m=masa subst.    ; M=masa  molara    ]

a.     n=56g : 28g/moli=2moli azot

        n=34g : 17g/moli=2moli NH3

b.   VN2=4,48dm³ = 4,48 l       [ 1litru=1dm³ ]

        n=4,48litri : 22,4litri/moli  = 0,2moli azot

        n=4,48 litri : 22,4 litri/moli =0,2 moli  NH3

c.     1mol N2--------------6,023.10²³ molecule

       x-----------------------9,033.10²³ molecule

x=9,033 .10²³ :6,023.10²³ =1,499 moli N2

       1mol NH3-----------------6,023.10²³molecule NH3

        y---------------------------9,033 .10²³molecule

        y=9,033.10²³ : 6,023.10²³ =1,499 moli NH3

MNH3=14+3=17------>17g/moli

MN2=2.14=28------->28g/moli