Question

Cine ma ajuta si pe mine??Va rog!!!

Answer 1

T1
a)(5x+4)(2x-1+2x+5)=(5x+4)(4x+4)=4(5x+4)(x+1)
b)(5x-3)(x-2-x-9)=(5x-3)(-11)=33-55x=11(3-5x)
c)9x²-6√5x+5+45x²+6√5x+1-28x²+5=26x²+11

T2
a)5(a-b)
b)(x+7)(3x-4-2x+5)=(x+7)(x-1)
c)(2x-7)(2x+7)
d)[3(x+3)-2x][3(x+3)+2x]=(3x+9-2x)(3x+9+2x)=(x+9)(5x+9)
e)5(x²-2x+1)=5(x-1)²
f)(a+1)²-b²=(a+1-b)(a+1+b)

T3
a)Dupa regruparea termenilor avem a²-2ab+b²+a-b=(a-b)²+(a-b)
sau (a-b)(a-b+1) =>expresia este egala cu 1×(1+1) sau 2.
b)Dupa regruparea termenilor avem a²+2ab+b²+2(a+b)=(a+b)²+2(a+b)
sau (a+b)(a+b+2) =>expresia este egala cu 2×(2+2) sau 8.