Question

Cine mă ajută urgent. Coroană​

Answer 1

$3^{105}:(5^{221}:5^{220}-2)^{45}:27^{20}=\\3^{105}:(5^{221-220}-2)^{45}:27^{20}=\\3^{105}:(5^1-2)^{45}:27^{20}=\\3^{105}:3:27^{20}=\\3^{105-1}:(3^3)^{20}=\\3^{104}:3^{60}=\\3^{104-60}=3^{44}$

$4^{3} :2^{2} -18^0*[5^{10}:5^9-6^2*(7^{15}:7^{13}-7^2)=\\(2^2)^3:2^2-1*[5-36*(7^2-7^2)=\\2^6:2^2-1*(5-36*0)=\\2^4-1*5=\\16-5=11$

$25^0+37:[2*3^4-5*(2^7:2^4-3^2:3)^2]=\\1+37:[2*81-5*(2^3-3^2:3)^2]=\\1+37:[162-5*(2^3-3)^2]=\\1+37:[162-5*(8-3)^2]=\\1+37:(162-5*5^2)=\\1+37:(162-5^3)=\\1+37:(162-125)=\\1+37:37=1+1=2$

$7^3:[7^4:7^3:[7^5:7^4:7:(7^{10}:7^9-6^7:6^6)]]=\\7^3:7:[7:7:(7-6)]=\\7^2:(1:1)=\\49:1=49$

$1+[19-9*(5^3)^7:(5^7)^3]^{10}:1000^3=\\1+(19-9*5^{21}:5^{21})^{10}:(10^3)^3=\\1+(19-9*1)^{10}:10^9=\\1+(19-9)^{10}:10^9=\\1+10^{10}:10^9=\\1+10=11$

Ti-am facut cat am vazut din exercitii( PS: trebuia o poza mai mare)

_______Succes!_______