Question

cine mă ajută va rog frumos​

Answer 1

Răspuns:

1(a)-(2x+1)=(2x)²+2*2x+1²=4x²+4x+1

(b)-(x²-3)²=x⁴-2x*3+3²=x⁴-6x+9

(c)-6x²-4=(3x+2)(3x-2)

2(a)-(½x-2y)²-(½x+2y)²=8y²

b)-4x(5x-6)²+2(x-4)²=4x[(5x)²-2*5x*6+6²]+2[(x)²-3x*4+4²]=4x(25x²-60x+36)+2(x²-8x+16)=100x³-240x²+144x+2x²-16x+32=100x³-242x²+128x+32

c)-(√5x+3√2)²=[(√5)²+2*√5*3√2+(3√2)²=5x²+6√10+18