Question

cine mă ajuta vă rog mulțumesc!?
prin metoda substituiei..​

Answer 1

$\it \begin{cases}\it\sqrt3x-2y=7\\ \\ \it x+4y=-8+\sqrt3\ \Rightarrow\ x=-8+\sqrt3-4y\ \ \ \ (*)\end{cases}\\ \\ \\ \it\sqrt3x-2y=7\ \stackrel{(*)}{\Longrightarrow}\sqrt3(-8+\sqrt3-4y)-2y=7\ \Rightarrow\\ \\ \Rightarrow -8\sqrt3+3-4\sqrt3y-2y=7 \Rightarrow -8\sqrt3+3-7=4\sqrt3y+2y \Rightarrow \\ \\ \Rightarrow -8\sqrt3-4=2y(2\sqrt3+1) \Rightarrow 2(-4\sqrt3-2)=2y(2\sqrt3+1) |_{:2} \Rightarrow \\ \\ \Rightarrow$