Question

cine ma poate ajuta???​

Answer 1

$\displaystyle E(x)=\Bigg(\frac{^{5)}1+x}{2x} -\frac{^{2)}1+2x}{5x} \Bigg)\cdot \frac{10x}{x+3} =\frac{5(1+x)-2(1+2x)}{10x}\cdot \frac{10x}{x+3} =\\\\=\frac{5+5x-2-4x}{10x} \cdot \frac{10x}{x+3} =\frac{x+3}{10x} \cdot \frac{10x}{x+3} =1$