Question

cine ma poate ajuta?..

Answer 1

1.  Cl⁰  + 1e⁻ = 2Cl⁻¹ se reduce ; Cl2 = agent oxidant
     Cl⁰ = 2Cl⁺¹ + 1e⁻ se oxideaza ; Cl2 = agent reducator    
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reactie de autooxidoreducere
2KOH + Cl2 = KCl + KClO + H2O
2. Cl⁺⁵ +6e⁻ = Cl⁻¹   se reduce;  KClO3 = agent oxidant
    Cl ⁺⁵ = Cl⁺⁷ + 2e⁻ se oxideaza KClO3 = agent reducator    (autooxidoreducere)
4KClO3 = KCl + 3KClO4
3.  S²⁻ = S⁰ + 2e⁻  se oxideaza ; H2S = agent reducator
     S⁶⁺ + 6e⁻ = S⁰  se reduce ; H2SO4 = agent oxidant
3H2S + H2SO4 = 4S + 4H2O