Question

cine ma poate ajuta?​

Answer 1

Răspuns:

8

vo=0,0314m/s=31,4mm/s

T=1s

----------------------------

f=1/T=1/1=1  hertz

ω=2πf=2π·1=2π

v=ωA

314=2πA

A=31,4/2π=31,4/2*3,14=10/2=5mm

y=5sin(2πt)

9.y1=1

v1=2cm/s

y2=3cm

v2=1 cm/s

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y1=Asin(ωt+Ф) =1 =>y1=Asinx =1  unde  x=ωt+Ф

v1=ωAcos(ωt+Ф)=2  => v1=ωAcosx    x=ωt+Ф

y1/v1=Asinx/ωAcosx=1/2 =>

1/ωtgx=1/2=> ωtgx=2

tgx=2/ω rel1

y2=A(sinωt+Ф)= Asinx=3

v2=ωAcox=1

y2/v2=Asinx/ωAcosx =>

tgx/ω=3=>

tgx=3ω rel  2

Egalam  relatia  1  si  2

2/ω=3ω

ω²=2/3=0,(6)

v1=ωA

2=2/3A

A=3cm

Explicație: