Question

cine ma poate ajuta?
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Answer 1

a) $\frac{1}{4x^{2}} :\frac{5}{8x}=\frac{1}{4x^{2}} *\frac{8x}{5}=\frac{8x}{20x^{2}} =\frac{2}{5x}=0,4x$

b)$\frac{x+1}{x^{2}}:\frac{2x+2}{3x}=\frac{x+1}{x^{2}}*\frac{3x}{2*(x+1)}=\frac{3x*(x+1)}{2x^{2}*(x+1)}=\frac{3}{2x}=1,5x$