Question

cine ma poate ajuta di pe mn geometrie de la 1 la 5?

Answer 1

1. Perimetrul ABCD = 2(AB+BC) = 2 x (8+6) = 28 cm

2. ABCD = paralelogram → DAB = BCD = 38° si ADC = ABC. Dar A+B+C+D = 360° → 2A+2B = 360° → 2x38° +2xB = 360° → B = 144° = D.

3. Perimetrul ABCD = 2 x (AB+BC) = 2 x (8+10) = 36 cm.

4.  Perimetrtul ABCD = 2 x (AB+BC) → 30 = 2 x (6+BC) → 18 = 2x BC → BC = 9 cm.

5. a) 120 = 2(28+BC) → BC = 32cm → AB = 28cm

b) 120 = 2(2BC+BC) → BC =  40 → AB = 20cm

c)120 = 2(BC-8+BC) → BC = 46cm → AB = 14cm

d) 120 = 2(AB+AB/3) → AB = 45cm → BC = 15cm

e) 120 = 2(4AD+5+AD) → AD = 22cm → AB = 38cm

f) 120 = 2(AB+AB/5) → AB = AB = 50cm → BC = 10 cm.