Question

Cine ma poate ajuta este pentru un test
La cerinta calculati trebuie sa folosim reguli de calcul prescurtat.

Answer 1

Răspuns:

Explicație pas cu pas:

1)x(3-5)=-2x

2)2(x²-3x-x+5)=2(x²-4x+5)

3)4x²y³:(-2xy³)=-2x

4)2x²+x-6x-3=2x²-5x-3

5)(2x+1)²=4x²+4x+1

6)(x-3)²=x²-6x+9

7)25x²-1

8)(x+2+2x-1)(x+2-2x+1)+x²-25=(3x+1)(-x+3)+x²-25=-3x²-x+9x+3+x²-25=-2x²+8x-22=-2(x²-4x+11)

Calcule

1)(x+2)²

2)(x-3)²

3)(x-5)(x+5)

4)(1/2x-7))(1/2x+7)

5)(x+2)(x+3)

6)(X-1))x+7)

7)(x-3/2)(x-1)

8)x²(x-4)-(x-4)=(x-1)(x+1)(x-4)

Answer 2

1).

3x-5x=

(3-5)x=

-2x

2) 2x(x-3)-2(x-5)

2(x× (x-3)-(x-5)

2(x^2-3x-x+5)

2(x^2-4x+5)

3).4x^2y^3:(-2xy^3)

4x^2y^3:(-(2xy)^3)

- 4x^2y^3 totu supra (2xy)^3=

4x^2y^3 totu supra 8x^3y^3=

-1 supra 2x

4).(2x+1)(x-3)=

2x^2-6x+x-3=

2x^2-5x-3

5). (2x+1)^2=

(2x)^2 +2×2x × 1 +1^2

4x^2+4x+1

6).(x-3)^2=

x^2-2x×3+3^2=

x^2-6x+9

7).(5x-1)(5x+1)=

(5x)^2-1^2

25x^2-1

8).(x+2)^2-(2x-1)^2+(x+5)(x-5)=

x^2+4x+4-(4x^2-4x+1)+x^2-25=

x^2+4x+4-4x^2+4x-1+x^2-25=

-2x^2+8x-22

Descompuneti:

1).x^2+4x+4=

x^2+2× x × 2 + 2^2=

(x+2)^2

2).x^2-6x+9=

x^2+2×x×3+3^2=

(x+3)^2

3).x^2-25=

x^2-25=

(x-5)×(x+5)

Scuze doar atat am stiut