Question

Cine ma poate ajuta la ex1?

Answer 1

$\it log_6 3 = a \ \ \ \ (*) \\ \\ log_3 2= \dfrac{log_6 2}{log_6 3} = \dfrac{log_6\dfrac{6}{3}}{log_6 3} =\dfrac{log_6 6-log_63}{log_6 3} \ \stackrel{(*)}{=} \ \dfrac{1-a}{a}$