Question

Cine mă poate ajuta la matematică
$- \sqrt{ \frac{2}{7} \times } \sqrt{3 \ \frac{1}{2} } = \\ \\ \\ - 338 \div \sqrt{98 = } \\ \\ \\ \sqrt{ \frac{5.4}{9.4} } =$
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Answer 1

Răspuns:

Explicație pas cu pas:

$-\sqrt{\dfrac{2}{7} }* \sqrt{3\dfrac{1}{2} }=-\sqrt{\dfrac{2}{7} }*\sqrt{\dfrac{3*2+1}{2} }=-\sqrt{\dfrac{2}{7} }*\sqrt{\dfrac{7}{2} }=-\sqrt{\dfrac{2}{7}*\dfrac{7}{2} }=-\sqrt{1}=-1.\\-338:\sqrt{98} =-\dfrac{338}{\sqrt{49*2} }=-\dfrac{338}{7\sqrt{2} }=-\dfrac{338\sqrt{2} }{7*(\sqrt{2})^2 }=-\dfrac{338\sqrt{2} }{7*2}=-\dfrac{169\sqrt{2} }{7}.\\\sqrt{\dfrac{5,4}{9,4}}= \sqrt{\dfrac{54}{94}}=\sqrt{\dfrac{27}{49} }=\dfrac{\sqrt{27} }{\sqrt{49} }=\dfrac{\sqrt{9*3} }{7}=\dfrac{3\sqrt{3} }{7}.$