Question

Cine ma poate ajuta? Multumesc.

Answer 1

1) a) = 4a^2 + 4a + 1 - 4a^2 - 4a
        = 1

     b) (x + 1/x)^2 = x^2 + 2 + 1/x^2
Stii din datele problemei ca x^2 + 1/x^2 = 2, deci x + 1/x = 2+2 = 4

3) x^2 + 2x+4+(3x-3)(x+1) = 4x^2-4x-1
x^2 +2x+4+3x^2+3x-3x-3 = 4x^2-4x-1
2x-3=-4x-1
6x=2
x=1/3