Question

Cine ma poate ajuta si pe mine?

Answer 1

6.

$\it T. \ \ sinusurilor:\\ \\ \dfrac{AC}{sinB}=\dfrac{BC}{sinA} \Rightarrow sinB=\dfrac{AC\cdot sinA}{BC}=\dfrac{2\cdot sin30^o}{4}=\dfrac{2\cdot\dfrac{1}{2}}{4}=\dfrac{1}{4}$

7.

$\it T.\ P.\ \Rightarrow AC=5\ cm\\ \\ sinB=\dfrac{AC}{BC}=\dfrac{5}{13}$