Question

cine ma poate ajuta si pe mine va rog.calculati media aritmetica si media geometrica a numerelor:a)a=2,(6)+√0,69(4)+1,5;b=90×[0,1(6)+0,(3)]                                                                             b) a=(3intreg3/5)la puterea -1 +√0,0(3)×0.8(3);b=3intreg1/2×[0,125-0,25+(-1) la puterea-6]la puterea -1                                       

Answer 1

a)a=2,(6)+√0,69(4)+1,5 =8/3 +√625/900+15/10 = 8/3+5/6+3/2=(16+5+9)/2=15
   b=90×[0,1(6)+0,(3)] =90×(1/6+1/3) =90x(1+2)/6=90x1/2=45
ma =(15+45)/2=30
mg=√(15x45)=√675=15√3

b)a=(3 3/5)⁻¹ +√[0,0(3)×0.8(3)]=(18/5)⁻¹ +√(3/90×5/6)=5/18+√1/36 =5/18+1/6= = (5+3)/18=8/18=4/9=0,5
   b=3 1/2×[0,125-0,25+(-1⁻⁶]⁻¹ =7/2×[0,125-0,25+1]⁻¹ =7/2×(1,375)⁻¹ =
=7/2+1/1,375=7/2+0,(72)=7/2+72/99=7/2+8/11=(28+16/)22=44/22=2

ma =(0,5+2)/2=1,25
mg=√(0,5x2)=√1=1