Question

Cine ma poate ajuta subiectul al III-lea

Answer 1

-calculez moli carbid
n(niu)= m/M--> n=128g/52g/mol= 2,46mol carbid

-calculez moli acetilena
n(niu)= V/Vm--->  31,36l/22,4l/mol= 1,4mol

din ecuatie rezulta
1mol..............1mol
CaC+H2O---> C2H2+H2O
2,46mol..........2,46(teoretic)........dar rezulta ,practic, numai 1,4mol

eta= n,prx100/n, teor=> 1,4x100/ 2,46=........................calculeaza !!!!