Question

Cine ma poate ajuta urgent, va rog

Answer 1

C6H6 + H2SO4 => C6H5-SO3H + H2O
ms acid = 300 g
c acid=98%
md acid= c x ms / 100 = 98 x 300/100=294 g H2SO4 pur
randament (r)= 80%

98 g/mol H2SO4 ... 158.17 g/mol C6H5-SO3H
294 g H2SO4 ............a g C6H5-SO3H
a= 294 x 158.17 / 98 = 474.51 g C6H5-SO3H (mt-masa teoretica adica la r=100%)
r= mp/mt x 100
mp=masa practica
mp= mt x r / 100 => mp C6H5-SO3H = 474.51 x 80 /100 = 379.6 g C6H5-SO3H