Question

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Answer 1

CxH(2x-2) + O2 = xCO2 + (x-1)H2O
ΔH = x·HfCO2 + (x-1)HfH2O - Hf alchina
-1255,5 = - 393,5 x -  241,8(x-1) - 226,7
635,3x = 1270,6   x = 2   ⇒ alchina  = acetilena
Q = 0,7·1255,5·5,6/22,4 = 219,7125
Q = mcΔt +mλ
m(0,39·399 + 111) = 219,7125     m = 219,7125/266,61 = 0,824kg = 824g
10.
(3) CH3-CH2-CH2-CH3 ⇒ CH2=CH-CH=CH2 + 2H2   ΔH = ?
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(1)  CH3-CH2-CH2-CH3 ⇒ CH2=CH-CH2-CH3 + H2    ΔH1 = 125,87 kj
(2)  CH2=CH-CH2-CH3 ⇒ CH2=CH-CH=CH2 + H2       ΔH2 = 110,73 kj
(1) + (2) = (3) ⇒ ΔH = ΔH1 + ΔH2 = 236,5 kj 
legea conservarii energiei
b) n butan = 112/22,4 = 5kmoli  ΔH = 5000·236,5 = 1182500kj = 1182,5Mj
c) nC4H6 = 1183/236,5 = 5 moli
V = 5·22,4 = 112 l