Question

Cine mă va ajuta mersi​

Answer 1

a) 2a+2a^2+b+ab =

2a(1+a)+b(1+a) =

(1+a)(2a+b)

b) 3a+3a^2-b-ab =

3a(1+a)-b(1+a) =

(1+a)(3a-b)

c) 2x^2+4ax-3x-6a =

2x(x+2a)-3(x+2a) =

(x+2a)(2x-3)

d) xy(xy+1)+a(xy+1)

(xy+1)(xy+a)

e) a(b+c+m)+y(b+c+m) =

(b+c+m)(a+y)

f) xy(1-xy+x^2y^2)-a(1-xy+x^2y^2) =

(1-xy+x^2y^2)(xy-a)