cine poate rezolva ??va rog mult ajutatima
Răspunsuri la întrebare
Răspuns:
Explicație pas cu pas:
13a) (√2+√3) - (√3+√5) +(√5-√2) = 0
13b) (2/3-1/2) + (2·6-5/2)-29/3=4/6+12-5/2-29/3= 4/6_72/6-15/6-58/6 = 72/6-69/6 = 3/6 = 1/2
13c) 3·5(2+3/2-1):√5+ (14√5/15-3√5/15+12√5/5)·5/47 = (3·5·5/2):√5+[(14√5-3√5+36√5)/3]·5/47= 75√5/(2·5) + 47√5/(3·47) = 15√5/2+√5/3= 47√5/6
13d) (5/2√7-2√7/7+3/2√7):1/√7+ √14/2(√14-√14/14+√14/7-3√14/14)= (5/2-2+3/2) +14/2(1-1/14+1/7-3/14) = 2+14/2(8/7-2/7)= 2+14/2·6/7= 2+6=8
14a) [(6√2+10)/10 - (√2+4)/4]·[(6√2-4)/6-(4√2-4)/4]= (12√2+20-5√2-20)/20 · (12√2-8-12√2+12)/12= 7√2/20 ·4/12= 7√2/60
14b) [12/3+(12-3√12)/12]·(2√6/6-3√6/2-12√6/12) = (60-3√12)/12·(12√6-18√6-12√6)/12= (60-3√12)/12 ·(-18√6/12) = (20-2√3)/4·(-3√6/2) = (10-√3)·(-3√6)/4 = (3√18-30√6)/4 = (9√2-30√6)/4
14c) (5√5/15-√5/10+4√5/3·5):(3√10+√10/30-62√10/60)= (9√5/5-√5/10):(90√10+√10-31√10)/30= 5√5/10:60√10/30 = √2/8
14d) [2√6(√3+√2)/2-6(18-√12)/6]· (4√18+12-12√2-8)= (3√2+2√3-18+2√3)·(12√2+12-12√2-8)= (3√2+2√3-18+2√3)·4= 12√2+16√3-72
15a) {[√7-(14-2√35)]/2√7 -2√10/10}·[2√5(√2-1)·√5/5-√2-1+3]= [√7-(7-√35)/√7-√10/5}·[(10√2-10)/5-√2+2]= (7√5/7-√10/5)·(2√2-2-√2+2) = (√5-√10/5)·√2= (5√10-2√5)/5
15b) √[(3√15)/5 ·3√5√6/2·6 ·2√2/1]: √[2√7)/3√6·(8√6)/3√7 ·1/16]= √(3√15·√30·√2)/20 : √1/9= √(3·30/20): 1/3 = √90/20:1/3 = 3/√2·3=3· 3√2/2=9√2/2