Question

Cine se pricepe bine la matematică și mă poate ajuta și pe mine la acest exercițiu ,vă rog frumos!

Answer 1

$\it =\Big(\dfrac{\ \ 3^{(3}}{9}+3\dfrac{\ \ 3^{(3}}{9}\Big):\Big(\dfrac{3}{10}+\dfrac{1}{3}\cdot\dfrac{2}{10}\Big)=\Big(\dfrac{1}{3}+3\dfrac{1}{3}\Big):\Big(\dfrac{^{3)}3}{\ \ 10}+\dfrac{2}{30}\Big)=3\dfrac{2}{3}:\dfrac{11}{30}=\\ \\ \\ =\dfrac{11}{3}\cdot\dfrac{30}{11}=10$

Answer 2

Răspuns:

10

Explicație pas cu pas:

$\Big[0.(3) + 3.(3)\Big] : \Big(0.3 + \frac{1}{3} \cdot 0.2 \Big) = \\ = \Big( \frac{3^{(3} }{9} + \frac{33 - 3}{9} \Big) : \Big( \frac{^{3)} 3}{10} + \frac{1}{3} \cdot \frac{2}{10}\Big) \\ = \Big( \frac{1}{3} + \frac{30^{(3} }{9} \Big) : \Big( \frac{9}{30} + \frac{2}{30}\Big) \\ = \Big( \frac{1}{3} + \frac{10}{3} \Big) : \frac{9 + 2}{30} = \frac{ \not11}{3} \cdot \frac{30}{ \not11} \\ = \frac{30^{(3} }{3} = \bf 10$