Question

cit e 1+2 ... + 100​

Answer 1

Folosim Suma lui Gauss:

1 + 2 + ... + 100 = 100 × ( 100 + 1 ) / 2 = 100 × 101 / 2 = 50 × 101 = 5050

Formula initiala:

1 + 2 + ... + n = n × ( n + 1 ) / 2

Answer 2

Răspuns:

Explicație pas cu pas:

Sn=n(n+1)/2

1+2+...+100=100(100+1)/2=100x101/2=50x101=5050