Question

Claculati a) 2*{16+39*[1+(309+99:11):53]}:17-34, b) 11*23-11*10+11*3. Ajutatima va rog

Answer 1

 a)
 2*{16+39*[1+(309+99:11):53]}:17-34=
2x{16+39x[1+(309+9):53]}:17-34=
2x{16+39x[1+318:53]}:17-34=
2x{16+39x[1+6]}:17-34=
2x{16+39x7}:17-3463=
2x{16+273}:17-34=
2x289:17-34=
578:17-34=
34-34=0
b)
11*23-11*10+11*3=
253-110+33=176

Se dau numerele a=333*5+33*5+3*5si b==333*5-33*5-3*5 aflati cu cat este mai mare suma numerelor decat diferenta lor
a=333*5+33*5+3*5
a=1665+165+15
a=1845
b=333*5-33*5-3*5
b=1665-165-15
b=1485
aflam suma:1845+1485=3330
aflam diferenta:1845-1485=360
aflam cu cat este mai mare suma decat diferenta:3330-360=2970